1993-10-23 - MTTF expressions for K = 1

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From: cme@ellisun.sw.stratus.com (Carl Ellison)
To: cypherpunks@toad.com
Message Hash: 7b4853ad7623ad345c43ac5cbba3315c3f212992cd437860bb9a701584fd9d2a
Message ID: <9310232341.AA04130@ellisun.sw.stratus.com>
Reply To: N/A
UTC Datetime: 1993-10-23 23:43:07 UTC
Raw Date: Sat, 23 Oct 93 16:43:07 PDT

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From: cme@ellisun.sw.stratus.com (Carl Ellison)
Date: Sat, 23 Oct 93 16:43:07 PDT
To: cypherpunks@toad.com
Subject: MTTF expressions for K = 1
Message-ID: <9310232341.AA04130@ellisun.sw.stratus.com>
MIME-Version: 1.0
Content-Type: text/plain


Sorry -- I left out the K=1 expressions from that paper.
They're a little more mundane (for Stratus) but of obvious interest here.
These are the most likely to be interesting to us.

Consider, for example, \lambda = 0.5 failures/year and
\mu = 52 repairs/year
for the kind of machines we're talking about (as opposed to Stratus
machines).  The resulting MTTF would be in years.

 - Carl


====================================================================

N =  2 ;  K =  1

\begin{equation}
\frac { 3\lambda + 1\mu }{ 2\lambda^2 }
\end{equation}


N =  3 ;  K =  1

\begin{equation}
\frac { 11\lambda^2 + 4\lambda\mu + 1\mu^2 }{ 6\lambda^3 }
\end{equation}


N =  4 ;  K =  1

\begin{equation}
\frac { 50\lambda^3 + 18\lambda^2\mu + 5\lambda\mu^2 + 1\mu^3 }{ 24\lambda^4 }
\end{equation}








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