From: charliemerritt@BIX.com
To: cypherpunks@toad.com
Message Hash: 82461dbc2deddee243dcd01f3d02d87210bb79596705d3c6836cec83dc88590e
Message ID: <9310042253.memo.37458@BIX.com>
Reply To: N/A
UTC Datetime: 1993-10-05 02:59:07 UTC
Raw Date: Mon, 4 Oct 93 19:59:07 PDT
From: charliemerritt@BIX.com
Date: Mon, 4 Oct 93 19:59:07 PDT
To: cypherpunks@toad.com
Subject: RSA EXAMPLE
Message-ID: <9310042253.memo.37458@BIX.com>
MIME-Version: 1.0
Content-Type: text/plain
cc:simons@peti.GUN.de (peter simons)
Dear Peter Simons,
In your example P=5 Q=7 you are indeed using small numbers.
Dont forget that D*E should equal 1 mod ( (p-1)*(q-1)/G).
G=gcd(p-1,q-1) so in your example D*E=1 mod 12.
D*E can not have common factors with 12 (2,3,4,6) etc.
If E=5 then D=5, a nonsense situation.
E=7 D=7
E=11 D=11
your key will not work
* * * * * * *
Try this: P=5 Q=11 N=55 G=2 (gcd(4,10)=2)
(p-1)*(q-1)=40 /G = 20
E=3 D=7 (D*E=21) 21 mod 20 = 1
Good key!
Message = 31
31^3=29791 mod 55=36 so cyphertext=36
36^7=78364164096 mod 55 = 31 so recovered message is indeed 31.
I hope this helps. Charlie Merritt [charliemerritt@bix.com]
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1993-10-05 (Mon, 4 Oct 93 19:59:07 PDT) - RSA EXAMPLE - charliemerritt@BIX.com