From: Kent Crispin <kent@bywater.songbird.com>
To: Cypherpunks Distributed Remailer <cypherpunks@ssz.com>
Message Hash: b73d00013fb8235f2634d39f9fe69b4207cdb776030c303f0f500eddfdaf3041
Message ID: <19971026191312.56933@bywater.songbird.com>
Reply To: <199710270042.SAA01737@einstein.ssz.com>
UTC Datetime: 1997-10-27 03:22:25 UTC
Raw Date: Mon, 27 Oct 1997 11:22:25 +0800
From: Kent Crispin <kent@bywater.songbird.com>
Date: Mon, 27 Oct 1997 11:22:25 +0800
To: Cypherpunks Distributed Remailer <cypherpunks@ssz.com>
Subject: Re: Orthogonal (fwd)
In-Reply-To: <199710270042.SAA01737@einstein.ssz.com>
Message-ID: <19971026191312.56933@bywater.songbird.com>
MIME-Version: 1.0
Content-Type: text/plain
On Sun, Oct 26, 1997 at 06:42:14PM -0600, Jim Choate wrote:
> > I do believe the use of the term this way was inspired by the
> > notion of a 'basis' in a vector space -- a set of orthogonal
> > vectors that span the space, ideally, unit vectors.
>
> Can you better define the term 'basis'?
This is basic linear algebra:
V a vector space -- the set of all (s1,s2,s3,...,sn), where si is an
element of the set of reals. A set of vectors {v1,v2,...,vm} in V is
linearly independent if there is no set of scalars {c1,c2,...,cm} with
at least one non-zero element such that sum(ci*vi) == 0. A set of
vectors S spans a vector space V iff every element of V can be expressed
as a linear combination of the elements of S. Finally, a basis for
V is a linearly independent set of vectors in V that spans V. A
space is finite dimensioned if it has a finite set for a basis. The
standard basis (or natural basis) for a vector space of dimension n
is th set of vectors
(1,0,0,...0)
(0,1,0,...0)
(0,0,1,...0)
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