From: Jim choate <ravage@bga.com>
To: hfinney@shell.portal.com (Hal)
Message Hash: 9c0f971f939e9688edb46b8cc871ae573e4f547c0a3e2fdaff59337e19828105
Message ID: <199403311354.AA01893@zoom.bga.com>
Reply To: <199403310605.WAA22633@jobe.shell.portal.com>
UTC Datetime: 1994-03-31 13:54:56 UTC
Raw Date: Thu, 31 Mar 94 05:54:56 PST
From: Jim choate <ravage@bga.com>
Date: Thu, 31 Mar 94 05:54:56 PST
To: hfinney@shell.portal.com (Hal)
Subject: Re: Bekenstein Bound (was: Crypto and new computing strategies)
In-Reply-To: <199403310605.WAA22633@jobe.shell.portal.com>
Message-ID: <199403311354.AA01893@zoom.bga.com>
MIME-Version: 1.0
Content-Type: text
>
> The Deutsch paper I quoted before was where I first heard of the Bekenstein
> Bound which Eric Hughes mentioned. According to Deutsch:
>
> "If the theory of the thermodynamics of black holes is trustworthy, no
> system enclosed by a surface with an appropriately defined area A can have
> more than a finite number
>
> N(A) = exp(A c^3 / 4 hbar G)
>
> of distinguishable accessible states (hbar is the Planck reduced constant,
> G is the gravitational constant, and c is the speed of light.)"
>
> The reference he gives is:
>
> Bekenstein, J.D. 1981 Phys Rev D v23, p287
>
> For those with calculators, c is approximately 3.00*10^10 cm/s, G is
> 6.67*10^-8 cm^3/g s^2, and hbar is 1.05*10^-27 g cm^2/s. N comes out
> to be pretty darn big by our standards!
>
> Hal
>
>
The problem I see with this is that there is no connection between a black holes
mass and surface area (it doesn't have one). In reference to the 'A' in the
above, is it the event horizon? A funny thing about black holes is that as the
mass increases the event horizon gets larger not smaller (ie gravitational
contraction).
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