1994-12-15 - Re: Algebra

Header Data

From: “Perry E. Metzger” <perry@imsi.com>
To: A5713643665@attpls.net (Tom Jones)
Message Hash: 7ab7342a2ade4d8f2e930561c01f1dbe8b57de1856dbb7997ac238a6c20ed2b3
Message ID: <9412152037.AA01349@snark.imsi.com>
Reply To: <2B20CAE5>
UTC Datetime: 1994-12-15 20:39:21 UTC
Raw Date: Thu, 15 Dec 94 12:39:21 PST

Raw message

From: "Perry E. Metzger" <perry@imsi.com>
Date: Thu, 15 Dec 94 12:39:21 PST
To: A5713643665@attpls.net (Tom Jones)
Subject: Re: Algebra
In-Reply-To: <2B20CAE5>
Message-ID: <9412152037.AA01349@snark.imsi.com>
MIME-Version: 1.0
Content-Type: text/plain



Tom Jones says:
> Dear Eric and Cypherpunks,
> 
> So, how is division defined in Fp?

Being an old fogey, I still refer to the field formed by the integers
modulo a prime by a gothic capital Z sub p.

In Z_p, you define division as the inverse of multiplcation, just as
in real life. One easy way to do this is to note that every number in
a field like this has a multiplicative inverse. Multiplying by the
multiplicative inverse of a number is the same as dividing by the
number. 

For the hell of it, make yourself a multiplication table for Z_5. Its
a quick exercise. Note that every number in Z_5 other than zero
possesses a multiplicative inverse -- that is, a number that it can be
multiplied against to yield 1. Step back and then observe,
experimentally, that for any three positive numbers in Z_5 A, B and C
such that A*B=C, that C*(B^-1)=A. One can, of course, prove that this
is the case rigorously...

Perry





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