From: Jiri Baum <jirib@sweeney.cs.monash.edu.au>
To: tcmay@got.net (Timothy C. May)
Message Hash: 080acb706089fec770617b879c1aa95695dc51750205bff1dcb7cd7505fc81fc
Message ID: <199512200022.LAA28002@sweeney.cs.monash.edu.au>
Reply To: <acfa2f2812021004d314@[205.199.118.202]>
UTC Datetime: 1995-12-20 00:27:58 UTC
Raw Date: Tue, 19 Dec 95 16:27:58 PST
From: Jiri Baum <jirib@sweeney.cs.monash.edu.au>
Date: Tue, 19 Dec 95 16:27:58 PST
To: tcmay@got.net (Timothy C. May)
Subject: Re: What ever happened to... Cray Comp/NSA co-development
In-Reply-To: <acfa2f2812021004d314@[205.199.118.202]>
Message-ID: <199512200022.LAA28002@sweeney.cs.monash.edu.au>
MIME-Version: 1.0
Content-Type: text/plain
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Hello,
tcmay wrote:
...
> Prime Factoring? Primes are easy to factor, of course. (Hint: Every prime
> has two factors.)
...
Can someone enlighten me as to what the two factors are?
With sensible definitions I've heard you either get one (just itself)
or four (itself [p], both units [1,-1] and the co-whatsitsname [-p]).
(Sorry to pick on tcmay, but usually when you factorise a number you
*never* put it a "1*", for example:
6 = 2*3
9 = 3*3*3
and
7 = 7
not
7 = 1*7
, so I suspect the usual statement would be "Every prime has one factor.".)
Or am I totally clueless?
Jiri
- --
If you want an answer, please mail to <jirib@cs.monash.edu.au>.
On sweeney, I may delete without reading!
PGP 463A14D5 (but it's at home so it'll take a day or two)
PGP EF0607F9 (but it's at uni so don't rely on it too much)
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