From: pstemari@bismark.cbis.com (Paul J. Ste. Marie)
To: ravage@bga.com
Message Hash: 248959edb7fe1a10acef63adbc52ca2734114dce53c2f85756b3f1d9737443e6
Message ID: <9409261722.AA27286@focis.sda.cbis.COM>
Reply To: <199409231755.MAA03386@zoom.bga.com>
UTC Datetime: 1994-09-26 17:25:39 UTC
Raw Date: Mon, 26 Sep 94 10:25:39 PDT
From: pstemari@bismark.cbis.com (Paul J. Ste. Marie)
Date: Mon, 26 Sep 94 10:25:39 PDT
To: ravage@bga.com
Subject: Fast Modular Factorial?
In-Reply-To: <199409231755.MAA03386@zoom.bga.com>
Message-ID: <9409261722.AA27286@focis.sda.cbis.COM>
MIME-Version: 1.0
Content-Type: text/plain
> > If (n!)mod x = 0 then there is a factor of x which is less than n. If
> > you can solve modular factorials, then you can solve for the largest
> > factor of x in logarithmic time. Obviously, nobody has found a method
> > to do either.
> >
> Just some thoughts...
...
> If x>n and x is not a prime then the result will again always be 0 since
> we can break x down into factors smaller than n and the previous argument
> removes the various factors.
This doesn't work--(x > n) & x not prime doesn't imply that x has a
factor less than n. That's only true if sqrt(x) >= n.
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