From: mpd@netcom.com (Mike Duvos)
To: cypherpunks@toad.com
Message Hash: 63abd661b5de0738acec2c1420629de755f64894042ed736234ff888ab35b87b
Message ID: <199409231634.JAA05777@netcom15.netcom.com>
Reply To: N/A
UTC Datetime: 1994-09-23 16:37:02 UTC
Raw Date: Fri, 23 Sep 94 09:37:02 PDT
From: mpd@netcom.com (Mike Duvos)
Date: Fri, 23 Sep 94 09:37:02 PDT
To: cypherpunks@toad.com
Subject: Fast Modular Factorial?
Message-ID: <199409231634.JAA05777@netcom15.netcom.com>
MIME-Version: 1.0
Content-Type: text/plain
A small question about large integer math...
We are all familar with the fact that x^(2^n) mod p may be
evaluated with only n modmults which accumulate geometrically
increasing powers of x.
Does a similar fast algorithm exist for computing (2^n)! mod p?
The only difference here is that one is accumulating a huge product
of consecutive integers instead of the same integer multiplied many
times. I am interested in values of n around several hundred.
I have played with this quite a bit and am unable to see any easy
exploitable symmetry which would lead to an efficient algorithm.
Any ideas?
--
Mike Duvos $ PGP 2.6 Public Key available $
mpd@netcom.com $ via Finger. $
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